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Video instructions and help with filling out and completing ss-4 fax number

Instructions and Help about ss-4 fax number

You get an EIN number from you all and I tried doing it online and it tells me that I must do it by telephone yes I am the trustee of the trust well I'd rather I'm basic I'm the executor into trust or the director but okay my name is Willie Cody co dy Willie WI ll ie Cody C OD Y yes area code for the US and the area code three two one eight seven seven nine nine zero zero I have the form in front of me yes no I check trust I don't know what do you mean by what type of a truss Oh revocable or irrevocable Music yes it's an irrevocable trust no I'm not from the United States okay yes I'll be the responsible party Willie Cody trust and the trade name will be WCT yes Dominica do em I n I ca yes that's because it's set for them whoever the other party is Music yes you can yes it actually hung up and so now I'm gonna have to call back again again what you need to know is this video is gonna be short it is just letting you guys know how this particular video was done so how this particular process is done so hold on I gotta call her right back because I'm very very not happy with the fact that it hung up it's a wonderful time in a neighborhood so I'm dialing a number on my cell phone and the call is being recorded on the cell phone but I figured since I am having to do the video again I might as well do it again this is gonna press one okay for this particular one this is the name of the trust it's gonna be that music and I'm gonna do the trade name as the initials and hello hello it has me on hold I don't think they like my number I think they have been watching the videos and but I haven't done a number in a while so I don't think that's the problem I just think that the person picked up the line and it went back to the same young lady and so she because it hangs up if you call back within an hour and that person's line is free to go right back to the same person you're gonna be doing it for banking purposes there is no reason for this right here banking purposes okay and you are not doing it as income you won't be making any monies and you won't be having any employees and this is not necessary what I did is I hung up because nobody spoke and so I think it is my phone number so because I am doing this call this way what we were going to do is I'm going to dial that number again and that is to give me a second to get their

FAQ

Should I fill out the SS-4 by hand or in the computer when I apply for EIN by fax?

I would fill out the SS-4 online via the IRS website. It is an instantaneous response and you have your official letter within seconds.

How do I fill out the SS-4 form for a new Delaware C-Corp to get an EIN?

You indicate this is a Delaware C Corp so check corporation and you will file Form 1120.Check that you are starting a new corporation.Date business started is the date you actually started the business.  Typically you would look on the paperwork from Delaware and put the date of incorporation.December is the standard closing month for most corporations. Unless you have a significant business reason to pick a different month use Dec.If you plan to pay yourself wages put one.  If you don't know put zero.Unless you are fairly sure you will owe payroll taxes the first year check that you will not have payroll or check that your liability will be less than \$1,000. Anything else and the IRS will expect you to file quarterly payroll tax returns.Indicate the type of SaaS services you will offer.

I want to create a web app that enables users to sign up/in, fill out a form, and then fax it to a fax machine. How to difficult is this to develop?

Are you sending yourself the fax or are they able to send the fax anywhere?  The latter has already been done numerous times.  There are email to fax and fax to email applications that have been available for decades.  I'm pretty certain that converting email to fax into app or form submission to fax is pretty trivial. They convert faxes to PDF's in many of these apps IIRC so anywhere you could view a PDF you could get a fax.

Can a non-USA citizen/resident obtain EIN?

You are asking for the domination number[1] of a certain Johnson graph[2] (please, no Big Lebowski jokes). In standard notation, this number is denoted $\gamma(J(90,5))$.(Note: I'm assuming that the “5 numbers drawn out of 90” are all different, which I believe is the case in most lotteries).The Johnson graph $J(90,5)$ is the graph whose vertices correspond to all the $5$-element subsets of $\{1,2,\ldots,90\}$, and two vertices are adjacent (connected with an edge) whenever the corresponding sets have $4$ elements in common. For example, $\{2,3,5,8,13\}$ is adjacent to $\{2,3,8,13,77\}$ but not to $\{2,3,5,9,14\}$.A dominating set for a graph is a set of vertices that is adjacent to each vertex not in the set. If you have a dominating set of tickets for $J(90,5)$, whatever the winning combination turns out to be has at least $4$ matches with a ticket in your hand.Calculating the size of a minimal dominating set, called the domination number, is computationally hard (the corresponding decision problem is NP-complete), and our graph $G=J(90,5)$ is no peanut: it has $N=\binom{90}{5}=43\,949\,268$ vertices, each with $d=5(90-5)=425$ neighbors.Of course, $G$ is a very specific and highly symmetric graph, so it's entirely possible that a minimal dominating set for it, or at least a relatively small dominating set, can be determined explicitly using some reasoning particular to this case.As with any optimization problem, we can pursue two competing paths: we may seek upper bounds by exhibiting some good dominating sets, and we can seek lower bounds by attempting to prove that every dominating set must be at least as large as some size $B$.Since the degree of $G$ is $425$, a dominating set must have at least $N/425$ elements, which sets a lower bound of $B=103\,411$ tickets. With fewer tickets than this you stand no chance of guaranteeing a four-element match. I suspect there is, in fact, a dominating set of this size, or very close to it.An equally obvious upper bound is obtained by simply scanning all $4$-number combinations $(a,b,c,d)$ in our range and filling in the fifth number arbitrarily. This yields a dominating set of size $\binom{90}{4}$. That's about 2.5 million tickets, which is far more than the theoretical lower bound, but it's also far less than the 43 million possible winning combinations.Of course, this is very wasteful. We made no use of the fact that each ticket can cover five $4$-number combinations, not just one. A better approach is to use a standard trick in design theory or coding theory: impose a linear constraint.Specifically, consider those combinations where the sum of the numbers is divisible by $90$. About $1/90$ of the combinations are special like that (The exact number is $488\,326$, which is just $N/90$ rounded up).Suppose you filled tickets with all of these special combinations. If the winning one happens to be special, you got it. If it's not, then in almost all cases it has four numbers in common with not only one but five of your special combinations.The reason is that given any winning combination $\{a,b,c,d,e\}$, you can keep $a,b,c$ and $d$ intact and find an appropriate fifth number $x$ (instead of $e$) which makes the sum $a+b+c+d+x$ divisible by $90$. The combination $\{a,b,c,d,x\}$ is then in your hand, unless it so happens that $x$ is identical to one of $a,b,c,d$. In this case you can try picking another element of the winning combo, say $d$, and try $\{a,b,c,y,e\}$ whose sum is divisible by $90$. Once again, we just need to hope that $y$ isn't identical to one of the other four numbers.For example, suppose the winning combination was $\{1,2,3,42,60\}$. The quadruplet $\{1,2,3,42\}$ is nowhere to be found among the special combinations, because the missing fifth number would have been $42$ itself. However, that's ok because $\{1,2,3,24,60\}$ is special, and matches four of the numbers in the winning combination. We can't “fix” the $60$, but we can fix any of the other numbers.In very rare instances, a winning combination may not be “fixable” at all. For example, suppose that the lottery was played with three numbers instead of five. The winning combination $\{10,40,70\}$ cannot be modified into a special combination by changing any single number.If that had happened in our case, we would simply have added a few tickets to cover for those pathological cases. But I'm quite sure that's not necessary: as far as I can tell there aren’t any “bad” combinations of five numbers in the range 1 through 90.The set of special tickets guarantees winning the lottery, but it’s still about 4.7x larger than the theoretical lower bound. This isn't surprising because, as we said, most winning combinations are actually covered by 5 of our tickets, though sometimes it's just 4. That's where this factor of 4.7 comes from.We can seek various pruning techniques to find winning sets of fewer tickets, but I couldn't yet find one that'll take you down to around 110,000 tickets. I'm 100% sure this is addressed in the literature, and I'll update this answer if I find anything.Footnotes[1] Dominating set - Wikipedia[2] Johnson graph - Wikipedia